hdu1023 Train Problem II 卡特兰数
Train Problem II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9002 Accepted Submission(s): 4817
1 2 3 10
1 2 5 16796HintThe result will be very large, so you may not process it by 32-bit integers.
#include <iostream> #include <cstring> #include <iomanip> #define base 10000 #define mlen 120iomanip头文件里面,setw()设置输出几位,如果不用setfill(char )的话 会用空格补位 用了setfill(char)补位会用指定的char。using namespace std;
int cat[mlen][mlen];
int mul(int a[],int n)
{
int carry=0;
for(int i=0;i<mlen;i++)
{
carry=carry+a[i]*n;
a[i]=carry%base;
carry=carry/base;
}
}int div(int a[],int n)
{
int bak=0;
for(int i=mlen-1;i>=0;i–)
{
bak=bak*base+a[i];
a[i]=bak/n;
bak=bak%n;
}
}int catalan()
{
memset(cat,0,sizeof(cat));
cat[0][0]=1;
cat[1][0]=1;
for(int i=2;i<mlen;i++)
{
memcpy(cat[i],cat[i-1],sizeof(cat[i-1]));
mul(cat[i],4*i-2);
div(cat[i],i+1);
}
}
int main()
{
int t;
catalan();
while(cin>>t)
{
int i=mlen-1;
while(cat[t][i]==0)
i–;
cout<<cat[t][i];
i–;
for(;i>=0;i–)
cout<<setfill(‘0’)<<setw(4)<<cat[t][i];
cout<<endl;
}
return 0;
}
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